• tetris11@lemmy.ml
      link
      fedilink
      arrow-up
      59
      ·
      23 hours ago

      The real question is, to how many iterations does the hamster say “Eh, good enough”

      • marcos@lemmy.world
        link
        fedilink
        arrow-up
        12
        ·
        edit-2
        21 hours ago

        Well, “hairs” are quantized phenomenon…

        So at some finite time, it will be all gone. At least if the thing is happening fast enough for it not to grow back at a similar time-frame.

        • esa@discuss.tchncs.de
          link
          fedilink
          arrow-up
          12
          ·
          21 hours ago

          Kinda. At the last strand I expect them to switch to length.

          But yeah, at some point should be good enough

          • SkyeStarfall@lemmy.blahaj.zone
            link
            fedilink
            arrow-up
            2
            ·
            edit-2
            19 hours ago

            But hair is still made up of discrete quantity of “stuff”

            Well, eventually you get to a point where hairs grow quickly enough that the haircuts effectively stop. I think the sum total of hair material you trend towards at the limit would be the sum of length of hair that grows during the time it takes to do a haircut. Whether it’s 1x or 2x of the hair growth amount depends on whether you measure at the start, or end, of the haircut

      • JackbyDev@programming.dev
        link
        fedilink
        English
        arrow-up
        7
        ·
        16 hours ago

        If you sum the hair removed from one lil guy you’ll get 1. If you sum the hair removed from all lil guys you’ll get the amount of lil guys.

        But yeah, you’re right. I think they’re looking at the problem differently. We don’t care about how much hair it has at each step. It can’t gain hair from a hair cut.

  • jsomae@lemmy.ml
    link
    fedilink
    arrow-up
    16
    arrow-down
    2
    ·
    18 hours ago

    it took me a while to understand that the guinea pig(?) in the window is meant to be the reflection of the one outside. Because the surface is roughly parallel with the viewer, the one outside is pointing to the left, so the flipped pig should also be pointing left.

  • 0ops@piefed.zip
    link
    fedilink
    English
    arrow-up
    24
    ·
    20 hours ago

    Well there’s a discrete number of hairs on that rodent thing, depending how the barber rounds they’ll have to cut the last hair eventually. Unless they only cut half of the last hair?

          • Jerb322@lemmy.world
            link
            fedilink
            arrow-up
            3
            ·
            17 hours ago

            I remember a comedian that had a joke similar to this. He had a volunteer come on stage, handed them a piece of paper and ask them to rip it in half. Then he told them “continue to rip it in half and eventually you’ll hear a large Bang”.

          • stupidcasey@lemmy.world
            link
            fedilink
            arrow-up
            3
            ·
            18 hours ago

            I mean technically there isn’t a finite number of atoms because there isn’t a finite number of anything because everything is part of the same energy field with varied energy states caught in self reinforcing patterns and when you “split” an atom you simply break the pattern allowing rapid entropy to a stable state.

            Tldr: the solution to this paradox is that it is impossible to split anything in half, you can only rearrange it.

  • reboot6675@sopuli.xyz
    link
    fedilink
    arrow-up
    48
    arrow-down
    1
    ·
    22 hours ago

    When I was a kid I encountered this problem when I wondered what would happen if I half-empty a bottle of soda, re-fill it with water, and repeat. Will it eventually become just water or will there always be some soda left? It boggled my mind for a while, then I forgot about it until I reached university calculus haha

    • palordrolap@fedia.io
      link
      fedilink
      arrow-up
      6
      ·
      18 hours ago

      The answer is that eventually all trace of the soda would be gone because there are only a finite number of atoms of “soda-stuff” and eventually you’ll end up with a situation where there’s only one molecule left, which - assuming that wasn’t the water part of soda in the first place - will have a 50% chance of being in the half that’s removed before the next dilution step. Theoretically it could survive infinitely many rounds of this, but the chance of that is basically zero.

      How many times is that though? For a litre of soda, the lower bound is about 85. A hundred ought to be more than enough. (And 300 times would be enough to dilute the entire observable universe assuming it was soluble in water, so that’s a reasonable upper bound.)

      You’d almost certainly stop tasting the soda quite a while before that though. After 20 dilutions you’re into parts per million soda to water.

      Things become more complicated if you replace the soda in this experiment with holy water. It seems to be agreed that 50/50 holy to regular water remains holy, but after that, some believe that dilution can be repeated forever (presumably being left to sit for a while after that step) while others claim the holiness disappears once the dilution goes beyond 51%, regardless.

      • brsrklf@jlai.lu
        link
        fedilink
        arrow-up
        3
        ·
        17 hours ago

        It’s easy to test for water holiness. If you drop the bottle and it bursts into flame molotov-cocktail style, it is still holy water.

        Source : Belmont et al., Wallachia, 1986

  • LifeInMultipleChoice@lemmy.world
    link
    fedilink
    arrow-up
    2
    ·
    edit-2
    18 hours ago

    This is one of those times you are hoping someone put Nair in the conditioner. It’s rare to yearn for, but that little guy needs the help

    • davidgro@lemmy.world
      link
      fedilink
      arrow-up
      1
      ·
      18 hours ago

      Only if each round of shaving, including the walking in and out, all take half as much time each round